[Physics] Is this Coriolis Force explanation simplified

coriolis-effectforces

As air moves from high to low pressure in the northern hemisphere, it is deflected to the right by the Coriolis force

They use an example of a merry-go-round, which makes sense intuitively. An object pushed from the outer edge inward is deflected to the right if the merry go round is spinning counter-clockwise.

Applying that to winds converging on a low pressure system on the surface of earth: we are told that Coriolis Force causes the winds to deflect to the right.

Question: what about winds moving from north to south in this system? This seems like it would be the 2D equivalent of pushing a ball from the inside to the outside of the merry go round, which if spinning counter-clockwise, would deflect to the left? (a ball pushed from inside to outside still deflects to the right, relative to co-rotating observer.)

Best Answer

I never did like the merry-go-round explanation for the Coriolis Effect. It may be intuitive for some, but I never could wrap my head around it. (And it's properly the Coriolis Effect, not Force. It's no more a "force" than the "force" pushing you against your car seat as your car accelerates.)

This works better for me: Imagine you plan on launching a projectile from the equator towards the North Pole. Your projectile will have an easterly velocity 1,039 mph, but let's, for the sake of simplicity, say it's 1,000 mph. As your projectile crosses, say, 20° north latitude it will still have that 1,000 mph eastward velocity, but the ground at 20° north latitude will have an eastward velocity of 940 mph (cosine 20° = .93969). IOW, the projectile will be travelling about 60 mph to the east faster than the ground. At 45° north latitude the ground will be moving at 707 mph, so your projectile will be traveling to the east almost 300 (293) mph faster than the ground.

Now imagine the opposite situation, launching a projectile from, say 40° north towards the equator. Your projectile will have an eastward velocity of 766 mph. As it crosses 20° north it will still have that eastward velocity of 766 mph, the ground will be travelling at 940 mph. IOW, the ground will be moving eastward 174 mph faster than the projectile, which will appear to deflecting towards the west.

In both cases the projectile will be appearing to deflect towards the right. From the equator that would be towards the east, but from north of the equator towards the south, the deflection would appear to be towards the west.

From a stationary observer above the earth, the projectile would appear to travel in a straight line while the earth rotated underneath it, which is in reality what is happening.

In the case of an air mass moving into a low pressure center, that air mass gets deflected towards the right as it enters the influence of the low, so it always enters the low toward its right. It then has no other direction to turn but towards the left.