So I know this is a pretty fundamental question, but I'll ask it any way. lets say you have a 12V battery, and the positive is connected to the negative directly by a wire with negligible resistance… is the voltage drop between the positive terminal and the negative terminal still 12V without a resistor? I know this is a short circuit by the way.
[Physics] is the voltage drop of a battery that is being short circuited the same as the battery’s advertised voltige
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Best Answer
No, quite opposite. For short-cut between both terminals, voltage drop between terminals is exactly 0 V! All of the advertised voltage drop is on the internal resistor of the battery.