In a set up such as the following:
I have read in many places that below resonance the driving force is in phase with the harmonic oscillator. I have also read that the driving oscillator is in phase with the harmonic oscillator, however, I would not expect both to be true.
In a harmonic oscillator, I am under the impression that the acceleration (proportional to force) and the displacement are in antiphase. Therefore one would not expect the driving force and driving oscillator to be in phase.
I was wondering if the force acting on the driving force is not the same as the force it applies on the harmonic oscillator, and that perhaps the displacement and applied force of a driving oscillator are in fact in phase.
Is this correct, or do the two original statements, in fact, contradict each other?
Thanks.
Best Answer
The driveR is applying a force say $F_0 \cos \omega t$ at the end of the "spring" remote from the "mass".
That end is executing simple harmonic motion and so the displacement of the end of the spring must be proportional to the force.
If there is no damping and you do not set your initial conditions carefully you are bound to have transient behaviour superimposed on steady state behaviour.
With damping you eventually on have steady state behaviour where the amplitude of the "mass" is constant.
To figure out and possibly remember what happens as the frequency of the driveR changes consider this.
You are holding the top of a spring and there is a mass attached to the bottom of the spring.
Very, very slowly you move the top of the spring up a certain distance and then do the same with the top of the spring moving down.
What will happen to the mass at the end of the spring?
Now this is where you have to put the mass into a beaker of water if you are actually doing the experiment or assume a reasonable amount of damping so that the transients die away reasonably quickly an do not mask the steady state motion.
The mass at the end of the spring will follow almost exactly the motion of your hand.
The driveR (your hand) and the driveN (the mass at the end of the spring) move in phase with one another.
As you move your hand up and down quicker but with the same amplitude the mass will start lagging behind the motion of your hand and the amplitude of the mass will increase.
It is difficult but not impossible to show this increase in amplitude of the driveN for constant amplitude driveR as the frequency of the driveR increases.
What is easier to show and see is that at higher frequencies of the driveR the amplitude of the driven decreases to a small value and the spring looks as though at times the top and bottom of the spring is being pulled in opposite direction.
The driveR (your hand) and the driveN (mass) are almost in anti-phase.
Here is a video produced by MIT replacing your hand with a wheel the rim of which is coupled by mechanical linkages to the top of a spring which has a mass at the other end.
The advantage of producing a video is that one can wait for the transients to die away before starting to record the motion.
Notice that the mass is damped using air resistance made larger by having a large horizontal circular disc attached to it.
The video shows very clearly that although the amplitude of the driveR (rod on the right) is constant the amplitude of the driveN, which at low frequency is the sane as that of the driveR, changes as the frequency of the driveR increase going though a maximum and then dropping off towards zero.
The phase changes are also clearly to see.
Another demonstration of mechanical resonance which shows the amplitude and phase relationships all at one time is Barton's pendula (sorry about the music) where an osculating pendulum bob of large mass acts as the driveR and pendula of different length with light bobs act as the driveN systems.
You have to wait for the transients to die down.
I chose this video because it also showed the side view which makes it a lot easier to observe both the amplitude of the motions of the pendulum bobs and their relative phase.