There is a quantity known as scattering cross section which is given as a function of frequency. It means the ratio of the scattered power by the particle to the ratio of the incident power on the particle.
Is radar cross section the same thing as scattering cross section? Some electromagnetic solvers (like CST studio) give radar cross section and absorption cross section only, so I guess it should be the same as scattering cross section.
Best Answer
From the CST Help:
That said, Total RCS is defined as the integral of scattered power divided by the intensity of the plane wave, that is, by definition, the scattering cross-section: $$\sigma_{\text{sca}} = \left(\frac{|E_0|^2}{2Z_0}\right)^{-1} P_{\text{sca}} = \left(\frac{|E_0|^2}{2Z_0}\right)^{-1} \frac{1}{2}\int\limits_{\text{around target}} \mathrm{Re}\left[\vec{E}_{\text{sca}} \times \vec{H}^{*}_{\text{sca}}\right]\cdot d\vec{s}$$ (here $E_0$ is the incident field, $Z_0 \simeq 377~\Omega$ is the free space impedance, $E_{\text{sca}}$ and $H_{\text{sca}}$ are the scattered fields).
Likewise, Total ACS is defined as the integral of all energy flux around the target, divided by the intensity: $$\sigma_{\text{abs}} = \left(\frac{|E_0|^2}{2Z_0}\right)^{-1} P_{\text{abs}} = \left(\frac{|E_0|^2}{2Z_0}\right)^{-1} \frac{1}{2}\int\limits_{\text{around target}} \mathrm{Re}\left[(\vec{E}_{0} + \vec{E}_{\text{sca}}) \times (\vec{H}^{*}_{0} + \vec{H}^{*}_{\text{sca}})\right]\cdot d\vec{s}$$ (Absorbed power is the power which entered the target, but did not leave it. For a non-absorbing target ingoing flux should be equal to outgoing flux, so the intergal would be equal to zero)