[Physics] Is it more efficient to drive fast uphill

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I know that for a rocket escaping the atmosphere, it's not efficient to travel slowly because even staying stationary consumes a lot of fuel. Does the same apply to a vehicle traveling uphill? In other words, is it more efficient for a car/bike/runner to accelerate and go over the hill quickly because energy is exerted during the climb even to "keep the vehicle stationary" and not just to travel the height and distance?

Best Answer

update: this answer is all wrong. See comments.

Ignoring optimal engine RPM and accelerations, assume there is no rolling resistance so that the only frictional force is air resistance.

$$F_{air} = cv^2$$

where $c$ is the drag coefficient for the given car and air conditions. The energy lost to it is:

$$E_{air} = dF_{air} = dcv^2$$ where $d$ is distance travelled. The net work energy to reach the top of a hill is $E_{height} = mgh$ where $h=d\sin(A)$. The energy the engine must provide is:

$$E_{air} + E_{height} = dcv^2 + mgd \sin(A)$$ Assume the most efficient $v$ is a constant so we can simply say $d = t/v$ where $t$ is time that $d$ was travelled. To find the $v$ that minimizes $E_{air} + E_{height}$ we take the derivative with respect to $v$, set it to zero and solve:

$$0 = tc - mgt \sin (A)/v^2\implies v = \sqrt{\frac{mg \sin(A)}{c}}$$

We can measure $c$ by rolling the car downhill. Let V be the terminal speed which is when air resistance equals the force from gravity.

$$cV^2 = mg \sin(A)$$

Solving for $c$ and plugging into equation for $v$ gives

$$v = V$$

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