In the photoelectric effect, the work function is the minimum amount of energy (per photon) needed to eject an electron from the surface of a metal. Is it possible to calculate this energy from the atomic properties of the metal (atomic number, atomic mass, electron configuration, etc.), and the properties of the lattice structure, in a way that doesn't require a complex computational model? (If so, how?) Or, if not, is there a simple formula in terms of the metal's atomic/lattice properties that can approximate it to within a few percent?
Solid-State Physics – How to Calculate the Work Function of a Metal
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There is definitely a relationship between the work function and ionisation energy of the elements. See the above figure in which I plotted the work functions (blue) and ionisation energies (yellow) of the elements named in the table of the former answer.
If you plot them against each other, it shows an definite, though loose, relationship. I bet there really is a relation between the two, but I do not know exactly what it is and why it exists.
Yes, an electric field will change the work function, but it is a very small change at ordinary values of the field. For example, if you apply say 10 volts to an electrode one centimetre away, giving a field of 1000 volts per metre, then the change in the work function will be negligible. I haven't got a number for you, but I expect the change would be lost in the noise in a photoelectric experiment.
The reason for this is that the work function is itself connected to an electric field, namely the one that comes about between the metal and an electron leaving it, and pulls the electron back in. This field is partly associated with the nearest atoms, and partly with the conductor as a whole. It can be overcome by applying a field of a similar size, and then the applied field will pull electrons out of the material, a process called electrical breakdown. This is what causes a spark when two conductors with a large voltage difference are brought near to one another. You need fields around a million volts per meter to cause such breakdown, I think.
It may surprise you that I wrote about such large fields, when the voltages in a typical photoelectric effect experiment are quite modest. It is because the workfunction voltage is developed over a small distance when an electron leaves a metal surface.
To conclude then, all this is almost entirely irrelevant to the photoelectric effect in the conditions that are normally used to study it, but in extreme conditions it is very relevant.
Best Answer
You can't just get it from the atomic properties, the electronic properties of a metal are dominated by "solid state"-type considerations, for instance, the fact that electrons live in a band structure rather than something more akin to the usual discrete levels that one learns about in QM 1.
Thankfully, Ashcroft and Mermin's classic book has a long discussion on the work function in chapter 18.
Their formula is $W=-\epsilon_F+W_s$, where $\epsilon_F$ is the Fermi energy, a quantity determined by the density of electrons and the properties of the crystal lattice of the metal; you can work out reasonable approximations to this for alkali metals by using the free electron approximation. $W_s$ is a quantity related to surface effects; for this term Ashcroft and Mermin give a model with a dipole moment per unit area of $P$, so that $W_s=-4\pi e P$.
I'm not sure whether you can really get "within a few percent" with such crude techniques, but it's certainly something that's calculable. In particular, getting a good approximation comes down to two things, 1) getting a handle on the band structure of the metal so that you can calculate $\epsilon_F$ accurately 2) having a good model for the surface of the metal.
There's a wrinkle here about how $\epsilon_F$ is defined. One can't just use the usual expression $\epsilon_F=\hbar^2k_F^2/2m$ as one needs to add in a term corresponding to the electrostatic energy of the ions, something like the Madelung constants.
Again, I recommend the book of Ashcroft and Mermin for this (and any other just-beyond-basic questions you might have about thinking about electrons in metals and semiconductors).
Just out of curiosity, I dug into the literature a little bit to see what researchers have done.
In 1971, Lang and Kohn were able to get work functions of simple metals to about 5% and noble metals to 15%. I think it would be possible to reproduce these calculations today quite easily.
A more recent paper (2005) by Da Silva, Stampfl, and Scheffler uses all-electron first principles calculations, as opposed to the more empirical fitted pseudopotential calculation that Lang and Kohn used. My impression from skimming the data is that they only get marginal agreement with experiment; in particular, I noticed that the experimental values seem to have quite a bit of variance in them, consistent with the fact that work function is strongly dependent on surface properties, which are hard to get consistent.
For example, for Aluminum along the 1 1 1 crystal plane, their calculations yield 4.21eV, compared to experimental values of 4.48, 4.24 and 4.33.
By comparison, Lang and Kohn's 1979 calculation gave 4.05 eV and they quoted an experimental value of 4.19 eV.
Apparently the last big review on calculating work functions of metals is this one by Hözl et al. from 1979. I didn't read it though.