[Physics] How to an electromagnetic wave behave as a particle

electromagnetic-radiationphotonsvisible-lightwave-particle-duality

Light is an electromagnetic wave and it possess both properties of a particle and wave.

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Looking at the image I can imagine how it behaves like a wave.
However, I'm not sure how it can behave like a particle.
If it behaves like a particle shouldn't it also look like one?

Best Answer

That's a deep question. The idea of particle-wave duality is behind the theory of quantum mechanics. In quantum mechanics the state of a system, be it a free particle for example, is given in term of a wave-function $\psi$ given by Schrodinger's equation $$i\hbar\frac{\partial\psi}{\partial t} =\hat{H}\psi$$ Whenever you measure something on a state, it collapses on a given eigenvector and the result of that measurement is given in term of the eigenvalue corresponding to that eigenvector.

The simple example is the one of a free particle, be it a photon, in one dimension for which the hamiltonian is just $$\hat{H} = \frac{\hat{p}^2}{2m} $$ so that Schrodinger's equation reads

$$i\hbar\frac{\partial\psi}{\partial t} = -\frac{\hbar^2}{2m}\frac{\partial^2\psi}{\partial x^2}$$

for which a solution is the following wavefunction

$$\psi(x,t) = e^{\frac{i}{\hbar}\left(px-\frac{p^2}{2m}t\right)} $$

The only measurable quantity for a free particle is it's momentum. Without going into the details, if you measure the momentum from this wavefunction you'll get $p$. So, by doing an experiment, what you'll measure is a particle with momentum $p$.

The theory for photons is actually more complicated than this since you absolutely need a relativistic formulation of quantum mechanics, but the idea behind it is just about the same.