[Physics] Force when distance between charge is zero

chargecoulombs-lawdistanceelectrostaticsforces

According to coulomb law

$$
F = \frac{q_1q_2}{r^2}
$$

I want to know what happens to force when $r=0$. If $F \to \infty$ then the charges can't be separated! But if an unlike charge of higher magnitude is placed beside any of $q_1$ or $q_2$ then it gets attracted. Can anyone clear me out?

Best Answer

If r = 0 then you have a single charge, so the problem reduces to the electromagnetic self-force problem. A charge will interact with the electric field it is in, and that includes the field due to its own charge.As long as the charge is not accelerating, one can pretend as if there is no self-force, but for accelerating charges, the self-force will lead to the emission of electromagnetic radiation.

The rigorous treatment of the self-force was until recently an unsolved problem. It was only recently rigorously solved