[Physics] Energy With Projectile Motion

energyenergy-conservationnewtonian-mechanicspotential energyprojectile

I just did a basic projectile motion experiment. What I did was build a small catapult out of small Popsicle sticks and rubber bands, and then I used it to launch a small ball at an angle above the ground. I wanted to figure out the total potential energy of the catapult when I pulled it back to launch the ball.

To do this, I figured that I should find the ball's total energy in both the x- and y- axis (ignoring anything in the z-axis). For the x-axis, I figured out the ball's horizontal Ek by dividing the horizontal distance it traveled by the time it took. This gave me the ball's horizontal speed, which I used to find its Ek. Due to the conservation of energy, I reasoned that the ball's energy in the x-axis must have been this value for the entire time (there were no horizontal forces acting on the ball, ignoring drag).

For the y-axis, I measured the distance above the ground that its highest point of flight was. Then I figured out the GPE at the highest point by using this value. Once again, I reasoned that the ball's energy at all times in the y-axis was this value, due to the conservation of energy (once again, ignoring drag).

At this point, I had the ball's energy in the x- axis and y-axis. To find the ball's total energy, I just added up both of the values. This told me how much potential energy was in the catapult when it was drawn back.

I was wondering if my steps were correct. Was what I did with adding up the energy in the x- and y- axis to find the total energy correct? I figured this was allowed since energy is a scalar, so direction shouldn't matter.

Best Answer

Talking about kinetic energy along the x- or y-axis is not quite correct, but close enough if you calculate it explicitly like this: $$K = \frac{1}{2}mv^2 = \frac{1}{2}m(v_x^2 + v_y^2) = \frac{1}{2}mv_x^2 + \frac{1}{2}mv_y^2$$

Otherwise, your calculations are correct. An easier method requiring only one measurement is to fire the projectile straight up while timing how long it's in the air. From this you can get the maximum height and thus the total energy.

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