What is the effect of dielectric medium in comparison to vacuum on electric field and electric flux?
permittivity relates to a material's ability to resist an electric
field (while, unfortunately, the word stem "permit" suggests the
inverse quantity).Source: Permittivity Wikipedia
Therefore, higher dielectric constant means higher relative permittivity which means more resistance to the electric field.
But a higher dielectric constant means an increase in electric flux which leads to a higher capacitance!
Please explain the resistance to the electric field with an increase in electric flux?
Best Answer
Dielectric constant $K$ is actually the same thing as relative permittivity, and it increases the overall permittivity $\epsilon$. So in general, whenever you see the permittivity of free space $\epsilon_0$ in an equation, if you're dealing with a dielectric, you can multiply it by the dielectric constant and see how the equation changes.
For example, since $C = \epsilon_0 \frac{A}{D}$, multiplying $\epsilon_0$ by $K$ increases capacitance by $K$. Since $\oint \mathbf E \cdot \mathrm d \mathbf A = \frac{Q}{\epsilon_0}$ by Gauss's Law, multiplying $\epsilon_0$ by $K$ decreases electric field magnitude by $K$.
There is no contradiction because there is no increase in electric flux. The dielectric decreases the electric field magnitude, which decreases the electric flux and decreases the voltage across a capacitor as well. $C = \frac{Q}{V}$ and the capacitance increases because the voltage decreases while the charge remains the same.