It says that in adiabatic process, the heat is constant but the temperature is not. My question is, if you increase the pressure, the temperature is going to rise as pV = kT. But we know that the energy, E = $\frac{3}{2}RT$
So if T is increased here, it must increase the Energy also. Where does the system get energy from? Does the increase of pressure contribute?
[Physics] Does the increase of pressure of a gas also increase the energy
ideal-gasthermodynamics
Related Solutions
By definition, $dS =\frac{dQ}{T}$, so an adiabatic process doesn't change entropy. But you can find more details at http://en.wikipedia.org/wiki/Adiabatic
A P-V diagram is a good way to show what happens as the area under the graph is the work done and the gradient for an isothermal change is always larger (less negative) than that for an adiabatic change (the gradients are negative).
Compression from a volume $V_i$ to a volume $V_f$ results in a higher final pressure for an adiabatic change $P_{fa}$ than for an isothermal change$P_{fi}$ and hence more work is done during the adiabatic change.
Because the temperature has increased after the adiabatic change the internal energy of the system after the adiabatic change is greater than that after the isothermal change for which there is no change.
Best Answer
To decrease the volume of the gas and hence increase its pressure work needs to be done. That is an external force must move through a distance.
The work done can be found by working out the integral $\int P \;dV$ which is the area under a Pressure, $P$, against volume, $V$, graph.