This might be a stupid question, but I'm a newbie to physics.
An object less dense than water (or any other fluid, but I'm going to use water for this example) floats normally on Earth when placed in water. But if the object was placed in a hypothetical place where there is no gravity and there is air, it would not float on water. So if the object was placed in water on a planet with more gravity than Earth, would it float more or would it float less, or float the same as on Earth?
Would it float more because it doesn't float without gravity, but it does float with Earth gravity, therefore it'd float even more with more gravity.
Or would it float less because more gravity would pull the object down, so it won't float as much.
Or would it'd float the exact same as on Earth because the above two scenarios cancel each other out.
EDIT: By "float more," I mean it rises to the surface of the water faster, and it takes more force to push it down. By "float less," I mean it rises to the surface of the water slower, and it takes less force to push it down.
Best Answer
The object would actually float exactly the same for both values of $g$. Let $V$ be the volume of the body, $d$ its relative density, and $V'$ be the volume inside water. Then for equilibrium of the body,
$V \cdot d \cdot g=V' \cdot 1 \cdot g$
So, $V'/V$ is independent of acceleration due to gravity.