[Physics] Conservation of momentum collision problem

homework-and-exercisesnewtonian-mechanics

The problems is as follows:

A 2000kg Ford was travelling south when it collided with your 1000kg sports car
travelling west. The two badly-damaged cars became entangled in the collision and
leave a skid mark that is 20 meters long in a direction 14◦ to the west of the
original direction of travel of the Excursion. The wealthy
Excursion driver hires a high-powered lawyer who accuses you of
speeding throughthe intersection. Use your knowledge, plus the police
officer’s report of the recoil direction, the skid length, and
knowledge that the coefficient of sliding friction between the tires
and road is $\mu=0.6$, to deduce the original velocities of both cars.
Were either of the cars exceeding the 30mph speed limit?

My attempt:
$$\sum \vec p_{initial}=2000v_1(-\hat x)+1000v_2(-\hat y)$$
$$\mu=\frac{F_f}{F_N},F_{N,(after collision)}=3000g,F_f=\mu g(3000)$$
So then using F=ma,
$$\mu g(3000)=(3000)a,a=\mu g$$
$$d=\frac 12 at^2+v_0t$$
In this case, I know that d=20meters, and $a=\mu g$. However, I do not have a $v_0$. My thought was to solve this for t, and then ssee what the cars final velocity was. After the collision, I know that the momentum is:
$$\sum \vec p_{after}=3000v_{after}(-\cos(14^\circ)\hat x-\sin(14^\circ) \hat y)$$
So I get lost on how to combine all of these equations to solve for the initial velocities of the two cars.

Best Answer

  1. Use the kinetic energy = work done by friction to find out the after impact velocity

    $$ \frac{1}{2} (m_{ford} + m_{sports}) v_{after}^2 = \mu (m_{ford} + m_{sports})\, g\, d $$

  2. Use conservation of linear momentum to solve for the initial velocities

    $$ \begin{aligned} m_{sports} v_{sports} & = (m_{ford} + m_{sports}) v_{after} \sin \theta \\ m_{ford} v_{ford} & = (m_{ford} + m_{sports}) v_{after} \cos \theta \end{aligned} $$

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