Pendulums – Comparing Conical and Simple Pendulums in Newtonian Mechanics

centrifugal forcecentripetal-forcefree-body-diagramnewtonian-mechanicsreference frames

I don't understand why the Tension $T$ on a conical pendulum and a simple pendulum are different.

In a simple pendulum, one would say that the tension of the rope is $T=mg \cos(\theta)$.

simple pendulum http://n8ppq.net/site_n8ppq/Physics/pendulum_files/image001.gif

However, in a conical pendulum (describing a circular motion), $mg=T \cos(\theta)$.

conical pendulum

The only difference I see in the set up of the two cases is that in the second one there is a velocity component that makes the bob go around in a circle.

I know that in the conical pendulum, the component $T \sin(\theta)$ would give the centripetal acceleration of the circular motion.

I've seen this everywhere. The two cases look pretty much the same to me, so I would be tempted to say one of them (rather the second one) is wrong.

Best Answer

A very nice thing you pointed out there which many people tend to skip...
Actually the fundamental rule of taking components of forces is that the coordinate axes should be perpendicular to the instantaneous direction of velocity or you can say the instantaneous direction of motion.
As the tension force is already perpendicular to the direction of motion, we resolve the $mg$ force (weight) into two components.
Hope this helps!

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