[Physics] conformal gauge

conformal-field-theorygaugegauge-theorygravity

I often see in physics articles on gravity such notion as conformal gauge and Weyl transformation.

They use Conformal gauge to change coordinates to transform metrics from arbitrary $$ds^2=g_{\mu \nu}dx^{\mu}dx^{\nu}$$ to $$ds^2=-e^{2\omega}dx^{+}dx^{-}. $$Equations of motion change dramatically (from my point of view) to a simpler form.

Also one can use Weyl transformations to convert the action in a simpler form, so the equations of motion change too.

I understand how to do technical details (I mean how to find new curvature, Christoffel symbols, how to write new action and equations of motion), but it seems to me that I DO NOT understand the meaning of these transformations.

Why do they call it "gauge"? I mean I know that in gauge theories gauge transformations do not change equations of motion and action, so they keep "physics" untouched. But it is not so in case of conformal gauge, isnt' it? And why are we satisfied when we obtain the solutions for metrics and fields in conformal gauge for action, which we get after weyl transformation etc? What does it tell us about initial system?

Best Answer

The two-dimensional Polyakov action for a string with worldsheet $\Sigma$ and worldsheet metric $h_{ab}$

$$ \frac{T}{2}\int_\Sigma \sqrt{-h}h^{ab}g_{\mu\nu}\partial_aX^\mu\partial_bX^\nu$$

has full conformal symmetry under the Virasoro algebra and under Weyl transformations1 , which can be seen as gauge degrees of freedom. It follows that we can always treat the worldsheet metric as being flat up to a Weyl factor (or even without it). Consequently,

$$h_{ab} = \mathrm{e}^{2\phi} \eta_{ab}$$

is known as the conformal gauge. It should be noted that Weyl symmetry is special to two worldsheet dimensions, since the action is not invariant under Weyl transformations for other dimensions due to $\sqrt{-h}\mapsto(\mathrm{e}^{2\phi})^{D/2}\sqrt{-h}$ in $D$ dimensions under a (local or global) Weyl transformation $h_{ab} \mapsto \mathrm{e}^{2\phi}h_{ab}$.


1For the difference between the two, see this question and answer.

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