OK, here is a complicated and clear explanation of what you are asking, which is also new to me: Soap is a complicated chemically molecule it breaks the high surface tension to allow bubbles, and also once in the air part of it protects the bubble from evaporation.
So it is an interplay between two components: surface tension and, as Georg points out,amphiphilic effects . It is not just the lower surface tension that creates bubbles, so for the other liquids you list an additive should be found that would work the same way soap works for water, not allowing evaporation.
This can be done by work and energy. Consider a spherical air bubble in water. The surface interface is air and water just like a water drop in air.
The net outward pressure on the bubble:
$$P_{net}=P_{in}-P_{out}$$
where $P_{in}$ is the pressure of the air bubble and $P_{out}$ is the water pressure just outside the bubble.
The work done by the net pressure to increase the radius of the bubble by $\mathrm dR$ is
$$dW=P_{net}\ A\ \mathrm dR=(P_{in}-P_{out})\ 4\ \pi\ R^2\ \mathrm dR$$
The change in surface area with the radius going from $R$ to $R+\mathrm dR$ is
$$dA=4\ \pi(R+\mathrm dR)^2-4\ \pi\ R^2$$
which when taking $$\mathrm dR^2=0$$ simplifies to
$$dA=8\ \pi\ R\ \mathrm dR$$
The change in surface energy of the bubble is
$$dE=dA\ T=8\ \pi\ R\ \mathrm dR\ T$$
where T is the surface tension.
Now equate work and energy.
$$4\ \pi\ R^2\mathrm dR (P_{in}-P_{out})=8\ \pi\ R\ \mathrm dR\ T$$
or
$$P_{in}-P_{out}=\frac{2T}{R}$$
Best Answer
The air inside is at a slightly higher pressure than the air outside, so the surface tension times the change in surface area is equal to the difference in pressure times the change in volume under an infinitesimal defomation, by the principle of virtual work.
The processes that make a bubble are
None of these three processes have been studied in quantitative detail as far as I know.