Bose-Einstein condensation occurs at 3 dimensions. However, it is not possible to happen at 1 or 2 dimensions; in fact I am able to prove this myself. What is the explanation for this?
[Physics] Bose-Einstein Condensation in lower dimensions
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Best Answer
For simplicity, I will consider non-interacting gases. The idea here is that there is a bound on the density of excited states in 3 and higher dimensions, whereas no such bound exists in 1 and 2 dimensions. This bound enforces a condensation of the gas particles into the ground state for 3 and higher dimensions but not in lower.
The details are a bit cumbersome to write down from scratch, so I will refer to some standard details and sketch out the non-trivial part. Check out eqns (7.31) and (7.32) of Mehran Kardar, Statistical physics of particles, where the average occupation number of a non relativistic gas is derived. Write down the same in $d$ dimensions. If you now convert the integral for the average occupation number into a dimensionless form, you will arrive at the generalization of eqn (7.34) for $d-$ dimensions given by
$$ n = \dfrac{g}{\lambda^d} f^1_{d/2}(z)$$
where
$$ f^1_{m}(z) = \dfrac{1}{(m-1)!} \int_{0}^{\infty} \dfrac{dx x^{m-1}}{z^{-1}e^x - 1}$$
This integral is finite for all values of $z$ if $d \geq 3$, and hence has a maximum value , whereas the same is not true for lower dimensions. In $d \geq 3$, we therefore have a bound on the density of excited states at $z = 1$, given by
$$ n _x = \dfrac{g}{\lambda^d} f^1_{d/2}(z) \leq n* = \dfrac{g}{\lambda^d} \zeta_{d/2}$$
where $\zeta_{d/2}$ is the max value of the number density of excited states at $z = 1$.
Since the integral is not finite and therefore no such maximum value exists for $d = 1,2$, hence there is no BEC in lower dimensions for this system.