Why is the sprectum of the cosmic microwave background radiation (or seems to be) that of a black body?
[Physics] black body and cosmic microwave background radiation
cosmic-rayscosmologythermal-radiation
Related Solutions
Beyond the fact that the cosmic microwave background (CMB) is a direct prediction of the big bang model, there is the question of how you would produce it in any other way. It is remarkably close to being isotropic and remarkably close to being a blackbody spectrum - i.e. it is almost a perfect blackbody radiation field.
A blackbody radiation field is emitted by material in complete thermodynamic equilibrium (CTE). An example would be the interior of a star. A requirement for (CTE) is that the matter and radiation field are characterised by the same temperature and that the material is "optically thick" - meaning that it is opaque to that radiation at basically all wavelengths.
Given that the universe is mainly made up of hydrogen, helium and (presently) traces of heavier elements, we can ask how is it possible to produce a perfect blackbody radiation field? Cold hydrogen and helium are transparent to microwaves. To make them opaque they need to be ionised, so that the free electrons can be a source of opacity at all wavelengths via Thomson scattering. But this requires much higher temperatures - about 3000 K.
How do we uniformly raise the temperature of a gas (adiabatically)? By squeezing it. A smaller, denser universe would be hot enough to have ionised hydrogen and would be opaque to the radiation within it. As it expanded and cooled, the electrons combined with protons to form atoms and the universe becomes transparent, but filled with a perfect blackbody radiation spectrum. The light, originally at a temperature of 3000 K and mainly in the visible and infrared, has had its wavelengths stretched by a factor of 1100 by expansion of the universe, meaning we now see it mainly as microwaves.
Additional evidence for this model is that the radiation field is not absolutely isotropic. These small ripples encode information such as the expansion rate of the universe at the time of (re)combination and the density of matter. When inferred from measurements, these parameters agree very closely with other determinations that are independent of the CMB, such as the Hubble redshift distance relationship and estimates of the primordial abundance of Deuterium and Helium.
There is now direct evidence that the CMB was hotter in the past and by exactly the amount predicted by an adiabatic expansion. The source of this evidence is measurements of the frequency-independence of the Sunyaev-Zel'dovich effect towards galaxy clusters (e.g. Luzzi et al. 2009); or more precisely by probing the excitation conditions in gas clouds at high redshift using even more distant quasars as probes (e.g. Srianand et al. 2008. New results have been published by Li et al. (2021). They describe measurements of the Sunyaev-Zel'dovich effect to hundreds of galaxy clusters in the redshift range $0.07<z<1.4$ and show that, the temperature of the CMB goes as $T_0(1 + z)^{0.983^{+0.032}_{-0.029}}$, consistent with an adiabatic expansion to 3%.
Best Answer
because this is the most probable configuration. Black-body light is the thermal equilibrium for light, so that anything that produces light which has a finite energy produces light that knocks around eventually to become blackbody light. The light we see was scrambled during the first 300,000 years by innumerable collisions with electrons and nuclei, and thermalized itself into equilibrium. There is no surprise when you see something in thermal equilibrium, the surprise in cosmology is that the temperature has small variations in different directions, which give us information about the inflationary process that gave birth to the light initially.