What i mean is for example exclusively red light comes in but gets reflected or refracted as blue or xray wavelength or whatever. Does this happen at all?
[Physics] Are there any materials that change the electromagnetic wavelength of visible light
electromagnetic-radiationmaterial-sciencequantum mechanicssolid-state-physicsvisible-light
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The certain film on the glass reflects blue light of wavelength 480nm, but does not reflect any red light of wavelength 640nm. ... If we say that it reflects blue light but no red light, does it mean that we actually see blue light only?
It depends which side of the glass you are observing from.
If you're on the same side as the source, you'll see the reflected blue light.
If you're on the other side, you'll see the transmitted red light.
As I understand, if something reflects a blue light that automatically means that red light and all other light is absorbed. Is that right?
No. For example, consider your bathroom mirror. It reflect blue light, and it also reflects red light.
Another possibility is it could reflect blue light and transmit (rather than absorbing) red light.
The polarized light you see in puddles of water or mirage, when driving on the highway, is a reflection from the sun which is why it's so bright. It's brighter than the rest of the light because it gets reflected off more reflective surfaces (puddles of water vs asphalt). The fact that it's polarized is merely a coincidence. Many displays (like the ones on LCD clock, for example) project polarized light which is much dimmer than the sun's reflection. It's the source of the light that makes the it bright, not the nature of the polarization.
The Brewster's angle boils down to the angle at which all light from the (polarized) incident ray is refracted, and none is reflected. So, to your first point, no, the refracted ray doe not gain energy as it gets refracted.
To your second point on orientation of the electric vectors, this illustration should help (a picture is worth 1000 words):
Best Answer
Going from low energy to high energy is remarkably commonplace. Anyone who carries a green LASER pointer may not realize it, but the origin of the electromagnetic radiation can be (and commonly is) an infrared AlGaAs laser diode operating at 808 nm, which is then pumped through a material such as Nd:YVO4 which increases the wavelength to 1064 nm it is then pumped through potassium titanyl phosphate which decreases the wavelength to 532 nm - effectively a frequency doubler.
There are filters and exact crystal alignment to take into account of in the manufacture of these items, but they are commonplace. (See here)