So I understand that a chaotic system is a deterministic system, which produces aperiodic long-term behaviour and is hyper-sensitive to initial conditions.
So are all aperiodic systems chaotic? Are there counter-examples?
Chaos Theory – Are All Aperiodic Systems Chaotic?
chaos theorycomplex systems
Related Solutions
It is true that the double pendulum exhibits integrable behavior, when the initial angles are very small, however, in general, it is very difficult to characterize the chaotic behavior of the double pendulum in terms of the initial angles. There are other representations which provide a clearer picture of its chaotic behavior.
The introductory section of the following articleby O. A. Richter, and reference therein describe the main characteristics of the double pendulum integrability (see here for the official journal version). I'll summarize here the main facts:
(Remarks: The numerical values correspond to a standard double pendulum of unit masses and unit rod lengths and unit acceleration due to gravity)
The total energy of the double pendulum is a constant of motion. The double pendulum possesses 4 equilibrium points corresponding to total energies $E= 0, 2, 4, 6$. The total energy determines the topology of the energy hypersurfaces, for $E<2$, the energy hypersurfaces are three spheres, while for $E>6$ , the energy hypersurfaces are three tori.
To further understand this point, in the case of very low energies, the system can be approximated (linearized) to an isotropic harmonic oscillator. The energy hypersurfaces are then of the form $x_1^2+x_2^2+p_1^2+p_2^2=E = const.$, while for the case of very large energies, the kinetic energy dominates and we can neglect gravity. In this case, there are two types of solutions of the equation of motion, one in which the outer rod rotates and the inner rod oscillates, and the second in which both rods rotate. The transition between the two types of solutions is determined by the value of the total angular $L$ momentum which becomes a constant of motion (due to the lack of gravity). For the standard double pendulum the transition occurs at $ L^2 = 2E$.
Both limits (small and large energies) correspond to integrable systems. This is well known, but here is a short explanation. To see that the isotropic harmonic oscillator is integrable, one needs to solve the equations of motion in polar coordinates. The polar angle just rotates with a constant angular velocity, and the radial coordinates oscillates in such a way that the trajectory has the shape of a two trip course through the donut hole drawn on the surface of a two-torus. This is the Liouville-Arnold torus (whose existence indicates the system's integrability) with respect to which the three sphere energy hypersurface is foliated.
In the high energy limit, a similar Liouville-Arnold torus exists when the inner rod oscillates and a torus generated by the two polar angles when the two angles rotate. (Here the exact solution is more difficult, see for example, the following article by Enolskii, Pronine, and Richter.
Now, since both limits of vanishing and very high energies correspond to integrable systems, the total energy also controls the system characteristics, but the dependence here is much more complicated. The transition from integrability to chaos and back as the total energy decreases from infinity to zero is described in figure 2 of Richter's article. There are a lot of details, but here are the main features: The figure correspond to the projection of the trajectories onto the plane spanned by the outer rod angle and the total angular momenta. For very large angular momentum, the projections of the trajectories are horizontal lines with constant angular momenta (which is a constant of motion). As the energy is reduced, two disjoint chaotic regions are formed, the integrable trajectories correspond to rational and irrational tori, together with stable resonances. At about E = 10.352 which corresponds to the golden winding ratio, all irrational tori vanish and a transition to global chaos occurs. The stable resonances also vanish eventually, at the low energies the resonances corresponding to the second integrable region start to appear.
A remark before. For chaos you need to have at least a 3D phase space.
A jerk equation consider a system of the form
$$\frac{\partial^3}{\partial t^3}x= f(x,\dot{x}, \ddot{x})$$
You can set auxiliar variables $y=\dot{x}$ and $z=\ddot{x}$ to obtain a three first order differential equation.
$$\dot{z}=f(x,y,z)$$ $$\dot{y}=z$$ $$\dot{x}=y$$
Depending on f, you can have chaos.
Best Answer
No.
A system might be, for instance, stochastic, random - which is certainly not an example of deterministic chaos, but is aperiodic.
You can also have quasiperiodic behavior, where the system comes close (but not exactly) to previous states, for which the simplest example is the circle map: $x \mapsto a+x$, where $a$ is irrational and $x$ is angle-like (e.g., $x\mapsto x\in[0,1)$). This dynamics is aperiodic, but not sensitive to initial conditions.
Also a damped harmonic oscillator doesn't come back to exactly the same state, since energy is being lost and, thus, is strictly not periodic (nor sensitive to initial conditions).
These deterministic aperiodic but non-chaotic behaviors are often called regular, as in the classic book Regular and Chaotic Dynamics by Lichtenberg and Lieberman.
A related question is Conditions for periodic motions in classical mechanics.