How can you get formula for 3-dimensional beam deflection at the free end of horizontal cantilever due to the cantilever's own gravitational load?
I assumed E= 160GPa, $\nu=0$, $\rho=2330kg/m^3$,
I tried to use this formula below, but it seems like there is height that I have to consider…
How do I start?
or, is it analytically not possible, and numerically obtainable?
Best Answer
Yes, that is where the factor $I$ in the equation comes in. It is known as the second moment of area, and for a rectangular beam of width $w$ and height $h$ it is
$$I = \frac{h^3w}{12}$$
The rest then follows from the equation you found...