Lorentz Model – Analyzing Imaginary and Real Parts in Electromagnetism

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I'm having some problems with the definition of the real and imaginary parts of the Lorentz model, we start from the definition of the permitivity $$\chi=\chi'+i\chi''=\frac{\omega_p^2}{\omega^2-\omega^2-i\omega \gamma}=\omega_p^2\frac{\omega_0^2-\omega^2}{(\omega_0^2-\omega^2)^2+(\omega \gamma)^2}+i\omega_p^2\frac{\omega \gamma}{(\omega_0^2-\omega^2)^2+(\omega \gamma)^2}$$

So we have,

\begin{align}
\chi'=\omega_p^2\frac{\omega_0^2-\omega^2}{(\omega_0^2-\omega^2)^2+(\omega \gamma)^2} \quad \xrightarrow{} \quad \text{Refractive index}\\
\chi''=\omega_p^2\frac{\omega \gamma}{(\omega_0^2-\omega^2)^2+(\omega \gamma)^2}\quad \xrightarrow{} \quad \text{Absorption} \qquad \,
\end{align}

This results are correct, you can see them in different sites for example MIT-Lorentz-Oscillator, and as we expect, for the absorption we get a Lorentzian, and for the refractive index we get a dispersive distribution, as is illustrated at the image,enter image description here
In the image are represented the permeabilities but are proportional. My doubt comes when if you plot the before expressions $\chi(\omega)$ you don't get the Lorentzian or the dispersive plots, in fact $\chi'$ is a even function, and $\chi''$ is a odd function, that doesnt match with the linked image… And I don't know what I'm doing wrong

Best Answer

Yeah, the imaginary part (loss) is supposed to be an odd function. For negative frequency, you have gain. Try plotting it!

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