Classical Mechanics – How to Justify that Work is a Transfer of Energy in the General Case

classical-mechanicsenergyenergy-conservationwork

By the work-energy theorem, we can justify that the work on a particle due to the net force equals the change in kinetic energy of the particle. In compact notation,
\begin{align}\tag{1}
W_{\text{net}} = \Delta KE.
\end{align}

This seems very useful. However, there are other contexts where work is used.

For example, we might want to find the potential energy of a certain configuration of charges in electrostatics. In that case, we imagine bringing charges from infinity together quasi-statically. By calculating the work needed to assemble the charge configuration, we say we have found the potential energy of the setup: $W = \Delta U$. But this time, we assume there is no kinetic energy is involved, because the process was quasi-static.

A more simple example is the case of trying to find gravitational potential energy, where we consider what it takes to lift something up quasi-statically (which can be done by applying a constant force $\vec{F} = mg\vec{e}_{z}$ to counteract $\vec{F}_{g}=-mg\vec{e}_{z}$), compute $W = \int_{0}^{h} mg\, dz = mgh$, and find $\Delta U = mgh$.

So now we might want to write
\begin{align}\tag{2}
W = \Delta KE + \Delta U.
\end{align}

I am aware we are no longer considering net work (which was crucial to the initial formulation of the work-energy theorem).

To make this more general, we might also consider internal energy (which will take into account thermal energy). So for example, maybe we have a system in which friction occurs internally, so there is work done by friction which "siphons" off energy into heat. In that case, if we define our system carefully, the work produced by a force external to the system will result in
\begin{align}\tag{3}
W_{\text{ext}} = \Delta KE + \Delta U + \Delta E_{\text{int}}.
\end{align}

My question is, are there theorems or (semi-)rigorous arguments that demonstrate the validity of equations $(2)$ and $(3)$? I suppose $(2)$ might be trivial if we qualify that the forces involved are conservative (so by definition we have $\vec{F} = -\nabla U$), but it's not clear exactly what rigorous argument can be made. And what about equation $(3)$? How is that rigorously justified?

Some related questions:

Best Answer

Sorry, but the scheme you are looking for turns out to be a dead-end.

We can start with the celebrated work-energy theorem. You will notice that it is always missing from a discussion of relativity, because whenever a relativity textbook author wants to establish work-energy theorem in the context of relativity, he or she will quickly come to the conclusion that the whole thing is WET (pardon the joke). There is simply no acceptable equivalent of work-energy theorem in SR, because, while you definitely can get the correct relations, it is more a case of ``Einstein's energy-momentum relations are the unique solution to the work-energy integral".

Instead, your Equation (3) is really part of the statement of the $1^\text{st}$ Law of Thermodynamics (which is really better stated as ``Energy is conserved, and heat is a form of energy").

Considering modern physics, with the central importance of Noether's theorem and its wide-ranging implications, it is much better to start the opposite direction: We assume interacting Lagrangians so that Poincaré invariance is manifest, and by Noether's theorem we essentially get energy and momentum conservation for free. Looking at it another way, what we are doing, is that we are acknowledging that energy and momentum conservation is the one most foundational and well-verified and sturdy bedrock (i.e. best to be picked to comprise the postulates), from which the rest of physics is meant to follow. And then we assume half of the $2^\text{nd}$ Law of Thermodynamics, with a specific form of entropy (I like Gibbs's version), and the rest of modern classical physics follows. This is the scheme that works well with quantum theory and is the viewpoint of standard physics today.


Another annoying thing: Work is actually not well-defined in the thermodynamic sense, especially if you have magnetic stuff. All the more reason to try and avoid both horrible concepts of heat and work, and instead work with well-established notions, and simply assume the validity of energy and momentum conservation.

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