Finding rate of change of the distance from an observer on earth to a satellite in orbit

distancedoppler effectnewtonian-mechanicssatellites

This is a satellite motion related question. To give context, imagine a satellite orbiting Earth at a distance 'R' from the center of the Earth at constant velocity 'v'. An observer on the surface of the Earth will be 'X' distance from the center of the Earth. At position 'p' where the observer is standing, there will be a horizon which the satellite can be seen in. This horizon can be represented as a chord perpendicular to the line 'X'. As the satellite comes above the horizon, the angle of elevation 'θ' increases. Overhead would be 90 degrees. 'θ' would range from 0 to 180 degrees. Considering all of this, a line of sight from the observer at 'p' can be drawn, which is essentially the distance from the observer to the satellite. (Refer to diagram attached). Note that the satellite is considered to pass overhead (overhead orbit) .My question is can anyone derive a function of distance 'd' with respect to time 't'? I know that finding a relation for a function of distance 'd' with reference to angle of elevation 'θ' is easy, but I require the x-axis to be time

visual aid of the question

The time period can be calculated from 'v' and 'R'. If the observer is standing at the center of the Earth, the rate of change will be constant. But since the observer is 'x' distance from the center, how would the 'd' value change according with time?

I want an function that I can plot. y axis would be the distance 'd' and x axis would be time, with 'v', 'R' and 'X' being values I can substitute and change.

difference between x-axis being theta vs time

Best Answer

I attached a sketch. Try to have a look at it

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