MATLAB: Wolfram alpha operation in matlab

wolfram alpha

how can i enter an expression and get the value of the variable that creates it?(like in wolfram alpha attached photo)

Thanks

Best Answer

Alternately,

syms x
solve(1.08393 == (1+x)/(1-x), x)

Related Solutions

MATLAB: How to expand a function to a polynomial expression

First, even though people think it is nice to write the shorthand in mathematics of

-1< x/4 <1

this is NOT a valid MATLAB condition in general. Yes, YOU know what it is intended to mean. But MATLAB typically does not see things like that.

Luckily, the symbolic toolbox is able to understand what you wrote.

syms x
assume(-1< x/4 <1)
assumptions
ans =
[ -1 < x/4, x/4 < 1]

In normal MATLAB expressions however, what you wrote will fail.

x= -5:5;
-1< x/4 <1
ans =
   1     1     0     0     0     0     0     0     0     0     0

Whereas we would have expected a different result.

(-1 < x/4) & (x/4 < 1)
ans =
   0     0     1     1     1     1     1     1     1     0     0

So always be careful when you make an assumption of how MATLAB will treat your favorite mathematical shorthand.

Regardless, to solve your problem, simplest is just:

taylor(x/(2*(x/4 - 1)) - 1/(x/4 - 1),'order',10)
ans =
- x^9/262144 - x^8/65536 - x^7/16384 - x^6/4096 - x^5/1024 - x^4/256 - x^3/64 - x^2/16 - x/4 + 1

MATLAB: How to implement the following

   x=rand(10,1);mu=randi(49,1,1)/100+0.0001% example
   for k=1:length(x)-1
       if  x(k)>=0 & x(k)<mu     
           x(k+1)=x(k)/mu 
       elseif x(k)>=mu & x(k)<0.5 
           x(k+1)=(x(k)-mu)/(0.5-mu)
       elseif x(k)>=0.5 & x(k)<1 
           x(k+1)=(1-x(k))/mu
       end
   end

Best Answer

Related Solutions

MATLAB: How to expand a function to a polynomial expression

MATLAB: How to implement the following

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