MATLAB: Why in the function below the ‘if’ statement does not have an ‘end’ line. the program runs normaly.

elseendfunctionifnormalyruns

Best Answer

The 'end' at the very bottom of your posted image is being interpreted by Matlab as the end of that if...else block.

Perhaps you thought that all functions need closing 'end' statements. That's not always true, see

>> doc function
>> doc end

as well as,

https://www.mathworks.com/matlabcentral/answers/81085-function-without-matching-end

Related Solutions

MATLAB: Matlab chokes on ‘end’ operator

Looks to me like it should be okay. Try putting parentheses around "end-1" and "end-10079" and see if that fixes it. If it doesn't then set

lastTimeIndex = length(TIME);
lastValIndex = size(VAL, 2);

and then use lastTimeIndex and lastValIndex instead of end and see if that works.

Do you want parentheses around "VAL(10,end)-60/86400" or not. That's another thing to check.

MATLAB: How to detect the ‘end’ directive in subsref

Overload the end method for your class as described on this documentation page.

The reason end was always taking the value 1 is probably because your object is a scalar (size [1 1]) that internally contains an array. Consider overloading size to return the size of that internal array if appropriate.

Best Answer

Related Solutions

MATLAB: Matlab chokes on ‘end’ operator

MATLAB: How to detect the ‘end’ directive in subsref

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