MATLAB: What’s wrong with the program

undefined

I'm completely confused.I have a large program and Matlab announce an error that I don't know what that is.

for F=1:PE*AE*RE

    GGP{F}=zeros(2,12);
    for i=1:12
        n=0;
        [GGP{F}(2,i),GGP{F}(1,i)]=cart2pol(GG{F}(1,i),GG{F}(2,i));
            for j=1:NodesTETA*NodesR*NodesZ
                if abs((GGP{F}(1,i)-p{j}(1))/Radiale)<1 && abs((GGP{F}(1,i)-p{j}(2))/peripherale)<1 && abs((GG{F}(3,i)-p{j}(3))/Axiale)<1
                    n=n+1;
                    NODZ{F,i}(n)=j;
                end
            end
    end
end
for F=1:PE*AE*RE
    for i=1:12
        *NODZ{F,i}=[3*NODZ{F,i}-2;3*NODZ{F,i}-1;3*NODZ{F,i}];*(line 193 error)
        NODZ{F,i}=NODZ{F,i}(:)';
    end
end

MATLAB error:

??? Undefined variable "NODZ" or class "NODZ".

Error in ==> ThesisMLS at 193

        NODZ{F,i}=[3*NODZ{F,i}-2;3*NODZ{F,i}-1;3*NODZ{F,i}];

Although I had identify NODZ in the first loop but it's undefined yet.

Best Answer

Evidently your "if" statement never became true so you never got inside to do this line:

NODZ{F,i}(n)=j;

So NODZ is undefined when you try to use it later. I don't know why it didn't become true, all I know is it didn't.

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MATLAB: Not enough input arguments

Your main function calls broyden with a seven element vector as its first input and a handle to the F function as its second input.

broyden(x,@F,7,0.001);

The broyden function calls feval to evaluate the F function with one input, the seven element vector. The f on this line does NOT refer to your f function but to the function handle stored in the variable named f.

fr = feval(f, xv);

You may have expected that MATLAB would automatically expand that vector to pass each element into F as a separate input w1 through w7.

function y = F(w1,w2,w3,w4,w5,w6,w7)

It doesn't. In this call w1 is a seven element vector and w2 through w7 do not exist. [You can add a call to the whos function as the first line inside your F function to check this; that whos output will show only w1 in the workspace.] Thus when you try to use w2 on this line inside F:

y1 = f(1/2,w1,w2);

MATLAB realizes you called F with not enough input arguments and so throws an error.

You could modify F so it accepts one input argument and refers to elements of that input argument. The first two lines would then be the following.

function y = F(w)
y1 = f(1/2,w(1),w(2));
end

Actually, I'd recommend preallocating y and filling it in as you go. Then you don't need to assemble the pieces together at the end.

function y = F(w)
y = zeros(7, 1);
y(1) = f(1/2,w(1),w(2));
end

Alternately you could modify your broyden function to pass each element of the vector into F individually. But I'd prefer the former, as among other things it's less typing.

fr = feval(f, xv(1), xv(2), xv(3), xv(4), xv(5), xv(6), xv(7));

MATLAB: Doesn’t this simple search program work

A simple test is type

[Dim{128}(1) Dim{128}(2)+D]

and

Dim{144}

and see if they match.

Best Answer

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MATLAB: Not enough input arguments

MATLAB: Doesn’t this simple search program work

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