MATLAB: What’s the problem

code

a = [1 2 3; 4 5 6; 7 8 9] * [0 1 0]’;

Best Answer

It works fine, IF you use a valid character for '

a = [1 2 3; 4 5 6; 7 8 9] * [0 1 0]'
a =
   2
   5
   8

The character you used for transpose was:

+'’'
ans =
      8217

But the valid transpose operator has ascii code:

+''''
ans =
    39

Related Solutions

MATLAB: Convert array into column vector – by row rather than column

Managed to achieve this by taking the transpose of matrix a first, and then performing the same operation.

 b = a';
 b(:)

MATLAB: What’s the solution

Here is one easy way, by generating one 3D array B and allocating all values of A in one go:

>> A = [7,4,1;4,5,6;3,6,9];
>> B = zeros(4,4,numel(A));
>> B(2,3,:) = A(:);

and testing each page of B, shows that it has all of the correct matrices:

>> B(:,:,1)
ans =
   0   0   0   0
   0   0   7   0
   0   0   0   0
   0   0   0   0
>> B(:,:,2)
ans =
   0   0   0   0
   0   0   4   0
   0   0   0   0
   0   0   0   0
>> B(:,:,3)
ans =
   0   0   0   0
   0   0   3   0
   0   0   0   0
   0   0   0   0
>> B(:,:,4)
ans =
   0   0   0   0
   0   0   4   0
   0   0   0   0
   0   0   0   0
etc

Best Answer

Related Solutions

MATLAB: Convert array into column vector – by row rather than column

MATLAB: What’s the solution

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