MATLAB: What’s the difference between code

Question

It's a stupid question but these two line of code do the same thing wthere dt1 is a constant. Is it right?

    prova= sum((out1.Y{i}(:,3:end)).^2)*dt1;
h=1;
for i=3:end;
y1=out.Y(:,i);   
prova(h)=sum(y1.^2)*dt1;    
h=h+1;
end;

Answer 1

Yes, they appear to be, at least to the limits of round-off error.