MATLAB: What is A/B when A and B are 1×3 row vectors

division

 This is so simple...i think i'm missing some thing

What is the result of A/B ???? (if A and B are same length row vectors)

ex: A=[1 2 3]; B=[4 5 6];

A/B in MAtlab gives me 0.4156

Best Answer

I want to know how this gives me 0.4156 ??? A/B is A*inv(B) ....

A/B is always defined as the least squares solution to the equation,

     A=X*B

     min. f(X) = norm(A-X*B)

In this case, the solution X has to be a scalar, since that is the matrix shape that can be left multiplied with B to produce another 1x3 matrix A. You can readily confirm that X=0.4156 is the minimizing value by plotting f(X),

    >> fplot(@(X)norm(A-X*B),[0.41,.42])

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MATLAB: How to convert spirographic values for r, R, and a to the code for a polar plot

If you want to plot a hypotrochoid, you do not need a polar plot. This code uses a Cartesian plot:

A = 5.0;
B = 0.5;
d = 2.0;
t = linspace(0, 2*pi, 500);
x=(A-B)*cos(t)+d*cos((A-B)/(B)*t);
y=(A-B)*sin(t)-d*sin((A-B)/(B)*t);
figure(1)
plot(x, y, '-r')
grid
axis equal

to produce this figure:

MATLAB: How to fit an exponential equation to raw data

This should get you started:

% some data
x = 1:20 ;
y = exp(-10 ./ (x .^ 1.1)) ;
yr = y + randn(size(y))/10 ; % add noise
% fit procedure
g = fittype(@(A,B,x) exp(-A ./ (x.^B)))
f = fit(x(:),yr(:), g )
% result
yh = f(x) ;
plot(x,yr,'bo',x,y,'b:.',x,yh,'rs-')

For more information, read the documentation on fit.

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Related Solutions

MATLAB: How to convert spirographic values for r, R, and a to the code for a polar plot

MATLAB: How to fit an exponential equation to raw data

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