MATLAB: What does the following MATLAB code do

rounding approximation

>> x=7.123456789;
>> n=7;
>> delta=0.5;
>> r=x*10^n+delta;
>> r=fix(r);
>> r=r/10^n;
>> disp(r)

Best Answer

It takes ‘x’, raises it to the ‘n’-th power, adds ‘delta’ to it, then rounds that result toward zero, divides that result by ‘10^n’ and prints the result.
The intent appears to be to round ‘x’ to 7 decimal places.
You can do that easily with the current version of the round function:
r = round(x, 7)
that will produce the same result.