MATLAB: To search fractal dimension

errorfractalsegmentasion

This is already the segmentation stage, and I want to find the fractal dimension but it has an error. Can someone help me?
image_folder = 'F:\kuliah\semester6\TA2\mencoba\output';
outfolder = 'F:\kuliah\semester6\TA2\mencoba\hasil';
if ~isdir(outfolder); mkdir(outfolder); end
files = dir(fullfile(image_folder, '*.jpg'));
 %I presume it has the variable map in it
for iFiles = 1:numel(files)
    thisfilename = fullfile(files(iFiles).folder,files(iFiles).name);
    [~, basename, ext] = fileparts(image_folder);
    citra = imread(thisfilename);
    %change to grayscale
    grayimg = rgb2gray(citra);
    figure, fig2=imshow(grayimg);
    %change to green channel
    green_channel = citra(:,:,2);
    figure, fig3=imshow(green_channel);
    %change to CLAHE (Contrast Limited Adaptive Histogram Equalization)
    CLAHE = adapthisteq(green_channel);
    figure, fig4=imshow(CLAHE);
    ER = edge(CLAHE, 'canny');
    EG = edge(CLAHE, 'canny');
    EB = edge(CLAHE, 'canny');
    anyedge = ER | EG | EB;
    figure, fig5=imshow(anyedge)
    size(fig5)
    fig = figure;
    outfile = fullfile(outfolder, sprintf('%s-coba-%03d.jpg', basename, iFiles));
    saveas(fig5, outfile);
    % yang dihitung dimensinya yaitu citra hasil segmentasi
    [n, r] = fboxcount(figure,'slope');
    %Perhitungan dimensi
    df = -diff(log(n))./diff(log(r));
    %Menampilkan hasil dimensi
    disp(['Df= ' num2str(mean(df(4:8)))]);
% % end
end

Best Answer

you are passing in something that isn't an rgb image.
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