MATLAB: This image correspond to a specimen deformed in the vertical direction. Would you have any suggestion to lift deformed pixels and make a “perfecly horizontal block”

image processingImage Processing Toolbox

NOTE: A mask can be easily created. Thank you.

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Just go along your mask finding the top line, then use circshift or imtranslate or simple indexing to lift the line.

[rows, columns] = size(mask);
for col = 1 : columns
    thisColumn = grayImage(:, col);
    topLine = find(mask(:, col), 1, 'first');
    thisColumn = [thisColumn(topLine:end), zeros(topLine-1, 1)];
    grayImage(:, col) = thisColumn;
end

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MATLAB: How to make all pixels under an assisted line boundary = 1

Try this (untested) with your mask to create a mask where the lower portion is true and the upper portion is false.:

[rows, columns] = size(mask); % Get size of your binary image with the line in it.
lastRow = ones(1, columns); % Initialize to top of image.
% Initialize a lower mask
lowerMask = false(rows, columns);
% Scan columns finding the last
for col = 1 : columns
    thisColumn = mask(:, col);
    t = find(thisColumn, 1, 'last');
    if ~isempty(t)
        lastRow(col) = t;
    end
    lowerMask(lastRow(col) : end, col) = true;
end
imshow(lowerMask);

MATLAB: Plot the deformed shape

Your syntax for applying the deformation is correct. Perhaps your values of Displacement are not what you expect? We don't have your data to test, but since you are are displacing all nodes, I wonder if the end result is just a linear translation of your structure. In other words, the result of the deformation is just moving the structure uniformly in x,y and z.

Can you attach you structural model and Displacement variable? You can save them to a mat file and attach them to your post using the paperclip icon.

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Related Solutions

MATLAB: How to make all pixels under an assisted line boundary = 1

MATLAB: Plot the deformed shape

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