The way I usually calculate and plot it:
t = linspace(0, 1, 1E+4);
s = sum(sin([0; 100; 200; 300]*2*pi*t*10)) .* randn*10;
Ts = mean(diff(t));
Fs = 1/Ts;
Fn = Fs/2;
L1 = numel(t);
FTs1 = fft(s)/L1;
Fv1 = linspace(0, 1, fix(L1/2)+1)*Fn;
Iv1 = 1:numel(Fv1);
L2 = 2^nextpow2(L1);
FTs2 = fft(s,L2)/L1;
Fv2 = linspace(0, 1, fix(L2/2)+1)*Fn;
Iv2 = 1:numel(Fv2);
figure
subplot(2,1,1)
plot(Fv1, abs(FTs1(Iv1))*2)
title('FFT of Original Signal')
xlabel('Frequency (Hz)')
ylabel('Amplitude')
grid
subplot(2,1,2)
plot(Fv2, abs(FTs2(Iv2))*2)
title('FFT of Zero-Padded Signal')
xlabel('Frequency (Hz)')
ylabel('Amplitude')
grid
This also demonstrates a way to increase the frequency resolution of the fft result by zero-padding it.
.
Best Answer