The secret to obtaining impulse responses lies in using the initial conditions that arise from impulse input. This approach allows the zero time duration of the impulse to be correctly modeled, rather than using an input signal of [1 0 0 0 ...].
Consider the following proof:
xdot = ax + bu
x = int(ax+bu)dt
= a*int(x)dt + b*int(u)dt
For the impulse response, u is a delta function which has an area of one from -inf to +inf. So,
x = a*int(x)dt + b*1
= a*int(x)dt + b
We want to determine the value of x at t = 0 (i.e., the initial conditions that correspond to an impulse). Assume that from t = -inf to t = 0, x = 0. The result is that a*int(x) can be evaluated from 0 to time t. We are interested in the initial condition (t = 0), which leaves a*int(x)dt to be evaluated from t = 0 to t = 0.
The result is:
and
Therefore, an impulse may be simulated by using an input of all zeros and initial conditions of b.
At first an appropriate state space model has to be defined:
a = -1;
b = 1;
c = 1;
d = 0;
sys = ss(a,b,c,d);
The following examples demonstrate various methods of obtaining impulse responses for the system.
1) Using the impulse command:
[y1,t1,x1] = impulse(sys);
plot(t1,y1)
2) Using the lsim command:
t2 = t1;
u = zeros(size(t2));
help lsim
[y2,t2,x2] = lsim(sys,u,t2,b);
plot(t2,y2)
3) Using the ode45 command:
Define the MATLAB file for the derivatives (see attachment 'fun.m'):
function xdot = fun(t,x)
xdot = -x;
Evaluate the function from t = 0 to t = 6:
[t3, y3] = ode45('fun',[0 6],b);
plot(t3,y3)
4) Using SIMULINK:
Remark: Additional to the description below, an appropriate Simulink (R2011b) model is attached, named 'obtain_impulse_response.mdl'. (You can directly start with point f, using this model)
a) Using a State-Space block, enter the a, b, c, and d matrices from above.
b) Specify b as the initial condition.
c) Use a constant input of zero and send the output to the workspace (use y4 as the return variable).
d) In the Simulation / Configuration Parameters / Data Import/Export enter t4 as the return variable for the simulations time vector.
e) Set the initial step size (in Solver Configuration Parameters) to 0.01 and the maximum step size to 0.1 and use the ode45 algorithm with a stop time of 6.
f) Run the simulation and plot t4 versus y4:
Best Answer