MATLAB: The problem with mean function

MATLABmeanreshape

i use this function to build the mean of vector:

    % mean_phase=mean(reshape(phase(:),25,[]))

i get this error with the size of the vector:

*Product of known dimensions, 25, not divisible into total number of elements*

How could i solve this Problem ?

Best Answer

 mean_phase=mean(reshape(phase(1:25*floor(numel(phase)/25)),25,[]))

Related Solutions

MATLAB: I have a 32 * 32 matrix .i want to take mean of each 44 so that the matrix is reduced to 88 array. Can anyone help me how to do that

Try use blockproc from Image Processing Toolbox

out = blockproc(A,[4 4],@(x)mean(x.data(:)));

variant without Image Processing Toolbox

[m,n] = size(A);
k = [4 4];
[ii, jj] = ndgrid(ceil((1:m)/k(1)),ceil((1:n)/k(2)));
out1 = accumarray([ii(:),jj(:)],A(:),[],@mean);

other variant

[m,n] = size(A);
k = [4 4];
C = mat2cell(A,k(1)*ones(m/k(1),1),k(2)*ones(n/k(2),1));
out = cellfun(@(x)mean(x(:)),C);

MATLAB: Finding minimal vector of matrix

The sortrows (link) function is one option:

M = [0.0026    0.0004
     0.0024    0.0003
     0.0023    0.0004
     0.0027    0.0003
     0.0023    0.0003
     0.0023    0.0001
     0.0025    0.0003
     0.0026    0.0002
     0.0023    0.0002
     0.0025    0.0003
     0.0027    0.0007];
[s,idx] = sortrows(M, [1 2]);
Out = idx(1)
Out =
     6

Best Answer

Related Solutions

MATLAB: I have a 32 * 32 matrix .i want to take mean of each 4*4 so that the matrix is reduced to 8*8 array. Can anyone help me how to do that

MATLAB: Finding minimal vector of matrix

Related Question

MATLAB: I have a 32 * 32 matrix .i want to take mean of each 44 so that the matrix is reduced to 88 array. Can anyone help me how to do that