Hello!I have a question about the order of free symbolic variables.
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syms X Yf=sin(X+Y);symvar(f,1)ans =X
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Since abs('Y'-'x')<abs('X'-'x'), why the free symbolic variable of 'f' is not'Y'?
Thanks a lot.
symbolic variables
syms X Yf=sin(X+Y);symvar(f,1)ans =X
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