for t=1:n [L(t)]=(1/(50)^(t)) [C(t)]=(1/(800))^(t);endFor the 1st line (L(t)) i need to use the interval 1:n however for the 2nd line i need from n:1. How do i change t without changing the interval in the for loop?
MATLAB: Taking a descend interval
descendforloophelpinterval
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There are some subtleties depending on how your 95% confidence interval was computed, but typically:
CI = tinv(.975,N-1)*std(x)/sqrt(N) T = mean(x)/std(x)*sqrt(N);so, if you have the sample mean M (M=mean(x)) and the confience interval CI, you can compute T as:
T = M/CI*tinv(.975,N-1);If you do not know the sample size N, you may assume N is relatively large and approximate the cumulative T distribution by a cumulative Normal distribution to get:
T = M/CI*1.96;The subtlety involves how your 95% CI was originally computed. The equation above assumes that this was a two-sided 95% interval (meaning that the population mean of x is expected to lie between M-CI and M+CI with 95% chance). Some times people use one-sided 95% intervals instead (meaning that the population mean of x is expected to be greater than M-CI with 95% chance) and that would mean that in the equations above you would need to change tinv(.975,N-1) to tinv(.95,N-1), and in the last equation change 1.96 to 1.64.
Use the sort index to change the order of columns in your data.
% Create demo data
rng('default')data = rand(8376, 35).*randi(100,1,35); % Compute median of each column
med = median(data); % Sort the columns of data by descending median order
[~, sortIdx] = sort(med,'descend'); dataDescend = data(:,sortIdx); % Plot the results
boxplot(dataDescend)
If you want to label the orginal column order,
set(gca, 'XTick', 1:numel(med), 'XTickLabel', sortIdx)xlabel('Original column order')
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