As you were already told in your last question, this is not a good idea: naming variables dynamically will make your code slow, buggy, and hard to follow. Read this to know why:
A much better solution is to learn to use indexing, which is fast and efficient:
>> a = {[1,9,79,3],[2,29,16,7,3],3,[4,74,3],[5,73,79,3],[6,56,3],[7,3]};
>> b = [79,3,74,10];
>> idc = cellfun(@(x)any(bsxfun(@eq,x,b(:)),2),a,'Uni',0);
>> out = cellfun(@(x)[a{x}],num2cell([idc{:}],2),'Uni',0);
which gives exactly the output vectors that you specified, inside the cell array out:
>> out{1}
ans =
1 9 79 3 5 73 79 3
>> out{2}
ans =
Columns 1 through 15
1 9 79 3 2 29 16 7 3 3 4 74 3 5 73
Columns 16 through 22
79 3 6 56 3 7 3
>> out{3}
ans =
4 74 3
>> out{4}
ans =
[]
Best Answer