MATLAB: Syntax to used unmatched values in matlab

matchingnotmatchingposition;syntax

c = [1,4,3]
sci = 1
a = sci;
findsamemember = ismember[c,a]

output will be

1 0 0

I am trying to get the values that are not matching with a in further process of the program. That is, the value that should be used as output in my next syntax is 4 and 3 (or at position 2 and 3)

How should I proceed with it?

Best Answer

idx=ismember(c,a);  % idx is logical index
c(~idx)*4 %multiply with whatever number you wish

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MATLAB: How to match and eliminate those values?

"i am not able to understand this"

Your code:

find(codes~=s))

first creates a logical array with the same size as codes, with 1 in every location where the arrays differ (you can see that the second row is all zero, where the data match exactly):

>> codes~=s
ans =
  0  0  1  1  0  0  1  1  1  1  0  0  1  1  0  0
  0  0  0  0  0  0  0  0  0  0  0  0  0  0  0  0
  0  1  0  1  0  1  0  1  1  0  1  0  1  0  1  0

You then use find to obtain the linear indices of those 1's. From the above matrix it is clear that the linear indices will be [6,7,10,12,...], but this is easy to check using MATLAB too:

>> find(codes~=s)
ans =
    6
    7
   10
   12
   18
   19
   22
   24
   25
   27
   28
   33
   37
   39
   40
   45

You then use these linear indices to select elements from codes, you can check this yourself too:

codes(6)  =  0
codes(7)  =  1
codes(10) =  1
codes(11) =  1
codes(12) =  1
... etc
codes(40) =  0
codes(45) =  1

and that is your output vector. Interesting, but ultimately not very useful for the task you described.

"how to match and eliminate those values??"

So far two people have advised to use setdiff: why are you not doing this?

Below is a copy of my answer to your earlier question , where I showed you two ways to achieve what you want:

Method one: setdiff:

>> s = [1,1,0,0,0,0,1,1,0,0,1,1,1,1,0,0]
s =
   1   1   0   0   0   0   1   1   0   0   1   1   1   1   0   0
>> c = [1,1,1,1,0,0,0,0,1,1,1,1,0,0,0,0;1,1,0,0,0,0,1,1,0,0,1,1,1,1,0,0;1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0]
c =
   1   1   1   1   0   0   0   0   1   1   1   1   0   0   0   0
   1   1   0   0   0   0   1   1   0   0   1   1   1   1   0   0
   1   0   0   1   0   1   1   0   1   0   0   1   0   1   1   0
>> z = setdiff(c,s,'rows')
z =
   1   0   0   1   0   1   1   0   1   0   0   1   0   1   1   0
   1   1   1   1   0   0   0   0   1   1   1   1   0   0   0   0

Note that setdiff can change the order of the rows, unless you use the 'stable' option:

   setdiff(c,s,'stable','rows')

Method two: indexing:

>> x = all(s==c,2);
>> z = c(~x,:)
z =
   1   1   1   1   0   0   0   0   1   1   1   1   0   0   0   0
   1   0   0   1   0   1   1   0   1   0   0   1   0   1   1   0

MATLAB: How to place a cell array in another cell array using ‘find’

If I understood correctly:

Ax = randi([0 1], 4, 960);  %Demo data. No way I'm reformating your example to make it valid matlab syntax. 
[row, col] = find(A);
blockidx = discretize(col, 1:60:size(A, 2));
Bx = accumarray([row, blockidx], col, [], @(c) {sort(c).'})

Note: I'm not working on the whole cell array here, just one of these 4x960 matrix as I've not understood what that had to do with the question. Possibly, you just want to above in a loop (or cellfun) operating over each element of the cell array.

Best Answer

Related Solutions

MATLAB: How to match and eliminate those values?

MATLAB: How to place a cell array in another cell array using ‘find’

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