MATLAB: Syntax help

circulant matrix

temp=randsrc(1,2);
temp=[temp zeros(1,4)];
temp1=transpose(temp);

temp1 =

I want to create circulant matrix with temp1 as first column… I have a circulant matrix with temp1 as first row :

h1=gallery('circul',temp1)

But I need it to be first column, Pls help me with it

Best Answer

h1 = h1';

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MATLAB: SYNTAX MATLAB

Eg.

x=1:20;   %i.e x=1 2 3.... 20
n=5;    % assign value of 5 to n
y1 = x(2:n)   % get second to nth (5th )value in x and put it in y1

Output of above

 y1 =
            2.00          3.00          4.00          5.00
 dt=1; %assign value of 1 to dt.. you can give any value
 t1 = n*dt - (2*dt:dt:n*dt);

frist term n*dt %multiply n (scalar) by dt a scalar

n*dt
ans =
          5.00

second term 2*dt:dt:n*dt % range twice dt to ntimes dt witht a difference of dt for above case 2*1:1:5*1 i.e (2:1:5)

2*dt:dt:n*dt
ans =
          2.00          3.00          4.00          5.00

ti=sub first term (scalar) -second term (array) (5-2, 5-3, 5-4, 5-5)

t1 = n*dt - (2*dt:dt:n*dt)
t1 =
          3.00          2.00          1.00             0

Hi, Since you mentioned that you just have to add the cyclic prefix, I am writing a code to add the cyclic prefix. The code can be shortened further. I have written in this way just for step-by-step illustration.

clc;
clear all;
length_message = 100;
message = randint(1,length_message,4); %Assuming QPSK symbols 
length_cyclic = 20;
starting = length_message - length_cyclic + 1;
cyclic_prefix = message(starting : end);
prefixed = horzcat(cyclic_prefix,message);

The removal of Prefix I leave on you. It is quite elementary and involves just matrix indexing. Accept the answer if you find it useful

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