MATLAB: Switch

complex numbers and vectors

Does matlab consider a complex number a vector, since i tried to make a switch, with a complex number being the decision making element and i got an error…i am going to solve the error, but i need to know if it is not caused by the a matlab compiler definition: complex number = vector ?

Best Answer

No, a complex number is 1x1 in MATLAB, not 2x1

Can you provide an example of where your switch fails?

   z = 1+1j;
   switch z
   case 1+1j
   disp('This executes');
   case 1+1j*2
   disp('This does not');
   end

Related Solutions

MATLAB: How can i plot whit the command plot a complex number with an imaginary part which is null? Can you make me an example of the code with this number

z=complex(1,0);
plot(z,'r+');

MATLAB: I keep getting a syntax error with the program??

in the If statement you need to use '==' Your first if statement would be

if x==0 & y==0 
 disp('This point is located at the origin.')

Your entire code

x=input('Enter value for x: '); 
y=input('Enter value for y: '); 
if x==0 & y==0 
    disp('This point is located at the origin.')
elseif x>0 & y==0 
    disp('This point is located on the x-axis.') 
elseif x==0 & y>0 
    disp('This point is located on the y-axis.') 
elseif x>0 & y>0 
    disp('This point is located in the first quadrant.') 
elseif x<0 & y>0 
    disp('This point is located in the second quadrant.') 
elseif x<0 & y<0 
    disp('This point is located in the third quadrant.') 
elseif x>0 & y<0 
    disp('This point is located in the fourth quadrant.') 
end

Best Answer

Related Solutions

MATLAB: How can i plot whit the command plot a complex number with an imaginary part which is null? Can you make me an example of the code with this number

MATLAB: I keep getting a syntax error with the program??

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