MATLAB: Suppressing output from user defined function

functionoutputsemicolon

function f=fib(n);
f=ones(n,1);
for i=1:n-2;
    f(i+2,1)=f(i+1,1)+f(i,1);
end;

i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.

Can anyone tell me why?

Best Answer

When you call your function use a semi colon at the end of the function to suppress the output.

try f=fib(n) and f=fib(n); in the command line to see the results

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MATLAB: When running a matlab function, it automatically prints the first output to the command window

Put a semi-colon after the call. For example instead of

my_test(3.5, 81)

put

my_test(3.5, 81);

MATLAB: Helped needed in Fibonacci Sequence code

Hello Cici. We can solve this by introducing another variable count into the function as shown below.

function[F_n, count] = Fibonacci(n, count)
    count = 1;
    
    if n == 2
        F_n = 1; 
    elseif n == 1
        F_n = 0;
    else
        [F_n_1, count_1] = Fibonacci(n-1);
        [F_n_2, count_2] = Fibonacci(n-2);
        F_n = F_n_1 + F_n_2;
        count = count + count_1 + count_2;
    end
end

Now your function returns both the

Fibonacci number as well as the number of times the function was called.

You may capture only the count in variable ans using this code snippet for the desired value of n.

[~, ans] = Fibonacci(n);

Hope this helps. :)

Best Answer

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MATLAB: When running a matlab function, it automatically prints the first output to the command window

MATLAB: Helped needed in Fibonacci Sequence code

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