MATLAB: Structuring of folder name

directoryparsing

how can i divide the path like C:/document/data/data-1/ into a structure which contain name of individual folder like {document, data, data-1} or just access the last folder into a variable like x = data-1.

Best Answer

Try this:

folder = 'C:/document/data/data-1/'
individualFolders = strsplit(folder, '/')
folder =
C:/document/data/data-1/
individualFolders = 
    'C:'    'document'    'data'    'data-1'    ''

Related Solutions

MATLAB: How to transfer folder structure to struct data

It does not sound like a good design to use the folder names as field names. Keeping the names in a cell string might be smarter:

data(k).value     = rand(10);
data(k).condition = {'folders', 'release', 'mode', 'const', 'var'};

Deeply nested structs are rarely useful for processing. But if you have a good reason to do so:

% Get all config.m files recursively (It is just a guess, that you need this):
BasePath = 'C:\Temp\';
FileList = dir(fullfile(BasePath, '**\config.m'));
data     = struct([]);
for iFile = 1:numel(FileList)
    Folder = FileList(iFile).path(numel(BasePath)+1:end);
    Keys   = strsplit(Folder, filesep);
    data.(Keys{1}).(Keys{2}).(Keys{3}).(Keys{4}).(Keys{5}) = ???
end

MATLAB: Excluding files with a certain keyword in them

Assuming you have the file name as a variable, I'll use myName:

myName = lower(myName);
idx = strfind(str,'composite');
if ~isempty(idx)
  %do nothing
else
  %do something
end

You need to find if 'Composite' is in the file name. strfind() returns the indices where it finds the match as a vector, if it doesn't find anything, it returns the empty vector. If you check whether or not the vector is empty, you can check whether or not 'Composite' is in the file name. I used lower() because strfind() is case sensitive. If case matters, you can just ignore the line

myName = lower(myName);

Best Answer

Related Solutions

MATLAB: How to transfer folder structure to struct data

MATLAB: Excluding files with a certain keyword in them

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