MATLAB: Storing double output into a single cell array

cell arraydoublefor loopMATLABmatrix

Hi, is there a way for me to store the output in a cell format, in a single matrix? I want to store each 'selectedlocal' as part of the cell array A. Right now, I have an error "conversion to double from cell is not possible".

Thank you!

A = zeros (9,8);
for k = 1:8
    sesslocal = cell2mat(locationsacc(k));
    for n = 1:9
    selectedlocal = find(sesslocal ==n); %%always change sesslocal
    A(n,k) = {selectedlocal};
    end 
end

Best Answer

zeros() to cell() and

A{n,k} = selectedlocal

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MATLAB: How to count the 1X1 cells in a cell array

a=cellfun(@numel,Out)
sum(a==1)

MATLAB: How to write a loop that does not increase by +1

A for loop can have any increment. Even a vector of numbers can be the increment. And it need not be in any order. Some examples:

% standard unit increment
for n = 1:10
  stuff
end
% increment of 2
for n = 2:2:12
  stuff
end
% only the prime numbers, that do not exceed 100
P = primes(100);
for n = P
  stuff
end
% an arbitrary set of numbers
nvals = [1 10 100 1000 10000 100000];
for n = nvals
  stuff
end
% an arbitrary set of numbers that need not be increasing, or even be integers
% the values might even be complex numbers.
nvals = [2 1 5 14 pi -1000 1 3 1.273435345 2+3i];
for n = nvals
  disp(n)
end
     2
     1
     5
    14
          3.14159265358979
       -1000
     1
     3
               1.273435345
                          2 +                     3i
                          
% the row vector input to for need not be a double precision vector.
% It may even be a cell vector
nvals = {1 pi,'bcde'};
for n = nvals
  disp(n)
end
    [1]
    [3.14159265358979]
    'bcde'
    
% or a character vector.
nvals = 'The quick brown fox jumped over the lazy dog'
for n = nvals
  disp(n)
end
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In a few cases, I've reported the value of n at each step through the loop. As you can see, the elements of the row vector may be any number. It can be of class uint8 or double, or even a cell vector.

Be careful of one thing however. The for statement operates as you would expect ONLY when given a ROW vector. It iterates across the COLUMNS of the input. So if the argument to for is a COLUMN vector, then the for loop runs for only one step. If it is a matrix, then the result will be a sequence of vectors!

% A 3x3 matrix, so there will be THREE iterations.
% n will be each of the columns of nvals in turn.
nvals = magic(3)
nvals =
     8     1     6
     3     5     7
     4     9     2
     
for n = nvals
  disp('A column')
  disp(n)
end
A column
     8
     3
     4
A column
     1
     5
     9
A column
     6
     7
     2

Best Answer

Related Solutions

MATLAB: How to count the 1X1 cells in a cell array

MATLAB: How to write a loop that does not increase by +1

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