MATLAB: Split the matrix for training a dataset based on the value in y axis using MATLAB

MATLABtraining set

I have a data set with matrix 168*1 and would like to extract training set based on the y axis value.

X – axis is the value from 0 to 180 (no. of cycle)

y – axis is the value from 0 to 2.1 (capacity)

I am looking to split the data set based on the value in y axis 1.4

any suggest ?

Note: I am able to split based on the percentage

numTimeStepsTrain = floor(0.7*numel(data));

Best Answer

It will split the dataset into two dataset x1, y1, and x2, y2. x1, y1 corresponds to value of y<1.4

index = y<1.4;
x1 = x(index);
y1 = y(index);
x2 = x(~index);
y2 = y(~index);

Related Solutions

MATLAB: Plot double y axis, 3 curves

If your data are column vector

[ax,h1,h2]=plotyy(x1,y1,x2,[y2 y3])
set(h1,'linestyle','none','marker','o','color','b')
set(h2(1),'linestyle','-','marker','o','color','r')
set(h2(2),'linestyle','-','marker','o','color','k')

MATLAB: Meshgrid

I assume that x and y have the same values as x1 and y1, but in a different order. You could do a search for each pair (x1,y1), but it's faster to sort the coordinates and then reshape Z. Here is an example with an actual image to give you the idea:

%%Set up the problem
load mandrill
Z = X; %rename image
nrows = size(Z,1); ncols = size(Z,2);
[x1,y1] = meshgrid(1:nrows,1:ncols);
x = x1(:); y = y1(:); Z = Z(:);
% Scramble the elements.
index = randperm(numel(Z));
x = x(index); y = y(index); Z = Z(index);
%%Now the problem is set up, unscramble x and y and then reshape Z.
xy = [x y];
[~,index] = sortrows(xy,[1 2]);
x = x(index); y = y(index); Z = Z(index);
Z = reshape(Z,nrows,ncols);
image(Z)

Of course, if x and y were originally obtained from a process like that in the previous cell, you won't need to sort.

Best Answer

Related Solutions

MATLAB: Plot double y axis, 3 curves

MATLAB: Meshgrid

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