Hi,
I am trying to solve the following equation for q in MATLAB, however, I get a message saying q is not defined.
solve(z1*(K1-1)/(q*(K1-1)+1)+z2*(K2-1)/(q*(K2-1)+1)+z3*(K3-1)/(q*(K3-1)+1)==0,q)
MATLAB: Solving an equation in MATLAB
solve
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How about the bar() function? Or the plot() function?
clc; % Clear the command window.
close all; % Close all figures (except those of imtool.)
clearvars;workspace; % Make sure the workspace panel is showing.
format long g;format compact;fontSize = 16;x1 = normrnd(10,1,[1,1000]) %normal distribution
x2 = gamrnd(10,1,[1,1000]) %gamma distribution
x3 = exprnd(10,[1,1000]) %exponential distribution
minValue = min([x1,x2,x3])maxValue = max([x1,x2,x3])numBins = 500; % Whatever you want.
edges = linspace(minValue, maxValue, numBins);counts1 = histcounts(x1, edges);counts2 = histcounts(x2, edges);counts3 = histcounts(x3, edges);% Plot with bars.
subplot(1, 2, 1);bar(edges(1:end-1), counts1, 'FaceColor', 'r');hold on;bar(edges(1:end-1), counts2, 'FaceColor', 'g');bar(edges(1:end-1), counts3, 'FaceColor', 'b');grid on;xlabel('Value', 'FontSize', 20)ylabel('Count', 'FontSize', 20)title('Bar Chart', 'FontSize', 20)legend('x1 histogram', 'x2 histogram', 'x3 histogram');% Plot with lines.
subplot(1, 2, 2);plot(edges(1:end-1), counts1, 'r-', 'LineWidth', 2);hold on;plot(edges(1:end-1), counts2, 'g-', 'LineWidth', 2);plot(edges(1:end-1), counts3, 'b-', 'LineWidth', 2);grid on;xlabel('Value', 'FontSize', 20)ylabel('Count', 'FontSize', 20)title('Line Plot', 'FontSize', 20)legend('x1 histogram', 'x2 histogram', 'x3 histogram');% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0, 0.04, 1, 0.96]);
That:
if trueis not part of the code, right? If it is, then you should be not even able to run the code....
Did you look at the output S? S has two solutions; it is a 2-by-1 one symbolic variable. To turn it into a 2-by-one double value, do:
S = subs(S);Now use the element-by-element division:
x1=z1./(S*(K1-1)+1);x2=z2./(S*(K2-1)+1);x3=z3./(S*(K3-1)+1);y1=K1*x1;y2=K2*x2;y3=K3*x3;
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