Hi guys, I need to solve this 3rd order ODE:
?⃛+2??̈+3??̇+4??=2, t≥0, ?̈(0)=?̇(0)=?(0)=0
This is my script:
[t,y] = ode45(@diffeq3,[0 50],[0;-1;1]);
plot(t,y)
function dy = diffeq3(t,y)
if t >= 0
dy(3) = 0
dy(2) = 0
dy(1) = 0
end
dy = zeros(3,1);
dy(1) = y(2);
dy(2) = y(3);
dy(3) = 2 – 2*y(3) – 3*y(2) – 4*y(1);
end
Did I do it right?
I got two questions, I got three curves which on is which?
And did I define t≥0, ?̈(0)=?̇(0)=?(0)=0 correct? With:
if t >= 0
dy(3) = 0
dy(2) = 0
dy(1) = 0
Thanks in advance for the help!
Best Answer