MATLAB: Solve equation f(x) = sin(x) − x^2 = 0 providing x is not equal 0 solution.

advanced numerical methods

Could you help me to calculate this question?

Best Answer

Plot it first. That will give you an idea of how best to search for at least one non-trivial solution:

f = @(x) sin(x) - x.^2;
x = linspace(-1, 1);
figure
plot(x, f(x))
grid
xs = fzero(f, 1)

produces:

xs =
         0.876726215395062

Related Solutions

MATLAB: Y = X . COS(X) . SIN(X)

You didn't say over what range to plot x, so I'm going to assume it's from -20 to 20. Adapt as needed:

% Choose a range for x and use 500 points.
X = linspace(-20, 20, 500);
% Create Y
Y = X .* cos(X) .* sin(X);
% Plot the function.
plot(X, Y, 'b-', 'LineWidth', 2);
grid on;
xlabel('X', 'FontSize', 15);
ylabel('Y', 'FontSize', 15);
title('Y = X .* cos(X) .* sin(X)', 'FontSize', 15);
axis equal;
% Make a black line at the x and y axes
line(xlim, [0, 0], 'Color', 'k', 'LineWidth', 2);
line([0, 0], ylim, 'Color', 'k', 'LineWidth', 2);

MATLAB: F(x)=sin(x)-x^5=0 providing x is not equals 0 ,function in the interval x [0,3]

>> [x0,fval]=fzero(@(x)sin(x)-x.^5,[0.8,1])
x0 =
    0.9610
fval =
  -1.1102e-16

Best Answer

Related Solutions

MATLAB: Y = X . COS(X) . SIN(X)

MATLAB: F(x)=sin(x)-x^5=0 providing x is not equals 0 ,function in the interval x [0,3]

Related Question