MATLAB: Solution of one variable parametric equation

equationfsolve

Dear colleagues,

I have an equation of the form x=c.tanh(a.x), where a and c are constants. I may ask for your kind suggestions to find the solution of equation.

Best regards, Imran

Best Answer

a=...;
c=...;
f=@(x)(x-c*tanh(a*x));
sol=fzero(f,1);
sol

By the way: x=0 is a solution.

Best wishes

Torsten.

Related Solutions

MATLAB: Multi-parametric fit

The nlinfit() function in the Statistics Toolbox does this type of fit. Here is a simple example that I wrote to help another poster:

% Here is an example of using nlinfit(). For simplicity, none of
% of the fitted parameters are actually nonlinear!
% Define the data to be fit
x=(0:1:10)'; % Explanatory variable
y = 5 + 3*x + 7*x.^2; % Response variable (if response were perfect)
y = y + 2*randn((size(x)));% Add some noise to response variable
% Define function that will be used to fit data
% (F is a vector of fitting parameters)
f = @(F,x) F(1) + F(2).*x + F(3).*x.^2;
F_fitted = nlinfit(x,y,f,[1 1 1]);
% Display fitted coefficients
disp(['F = ',num2str(F_fitted)])
% Plot the data and fit
figure(1)
plot(x,y,'*',x,f(F_fitted,x),'g');
legend('data','fit')

MATLAB: How to solve differential equation with MATLAB

Hi Torsten,

Actually I have understood the first equation and x is nearly 372000 derived. But it is a very high value and I can say it is not logical for my solution.

When I try an arbitrary value as nearly 375, the solution can be acceptable for me. 375 may be more logical for me.

That is to say; can there be a second answer of this equation?

Best regards,

Best Answer

Related Solutions

MATLAB: Multi-parametric fit

MATLAB: How to solve differential equation with MATLAB

Related Question